Maximum Score Of Spliced Array Solution in C++

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Code Solution


class Solution {
 public:
  int maximumsSplicedArray(vector& nums1, vector& nums2) {
    return max(kadane(nums1, nums2), kadane(nums2, nums1));
  }

 private:
  int kadane(const vector& nums1, const vector& nums2) {
    int gain = 0;
    int maxGain = 0;

    for (int i = 0; i < nums1.size(); ++i) {
      gain = max(0, gain + nums2[i] - nums1[i]);
      maxGain = max(maxGain, gain);
    }

    return maxGain + accumulate(nums1.begin(), nums1.end(), 0);
  }
};

Problem Description

So, you think you can just swap a few numbers between two arrays and magically get a higher score? Welcome to the world of the Maximum Score Of Spliced Array problem on LeetCode, where you can play the role of a number magician! The task is to find the maximum possible sum of one of the arrays after swapping some elements with the other array.

Imagine you have two jars of candies (let's call them nums1 and nums2). You can swap some candies between the jars, but you want to make sure that after the swap, you have the maximum number of candies possible. Sounds easy, right? Well, it’s like trying to convince your friend to trade their chocolate for your broccoli. Good luck with that!

Approach

The solution employs a modified version of Kadane's algorithm to calculate the maximum gain from swapping elements between the two arrays. The algorithm iterates through the arrays, calculating the potential gain from swapping elements and keeping track of the maximum gain found. Finally, it adds this maximum gain to the total sum of one of the arrays to get the final result.

Time and Space Complexity

Complexity	Details
Time Complexity	O(n), where n is the length of the input arrays. The algorithm processes each element of the arrays once.
Space Complexity	O(1), as it uses a constant amount of space for variables, regardless of the input size.

Real-World Example

Let’s say you’re at a party, and you have two types of snacks: chips (nums1) and cookies (nums2). You love cookies but your friend loves chips. If you swap some chips for cookies, you want to ensure you end up with the maximum number of snacks possible. This problem is just like that! You’re trying to maximize your snack collection by strategically swapping.